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PostPosted: Thu May 25, 2017 12:43 am 
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Joined: Sat Mar 04, 2017 5:43 pm
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Year and Trim: 2000 Pontiac Bonneville SSEI
Attached is a picture of my set-up

The LED set-up comes with 3 options: Hard wire install (left), cigarette lighter install (middle), and 9 + 9 V (18V) battery demo (right).

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The weird thing is when I connect the hard wire install plug (shown as the one connected to the color switch) to a 6-parallel switch, it made a loud 'pop' noise and then no longer works. Before breaking the lights, both of the other options (shown to the right of the 6-parallel switch) worked just fine. The equivalent 18 V battery didn't even destroy the lights, so why did the simple switch connected to the cigarette lighter outlet at 12 V destroy the lights?

Extra info: There are resistors built into the LED strip, and like I said, plugging them directly into the cigarette lighter did not break them, so why would introducing a switch break them? I am now using the switch for some other LEDs I bought and the switch is working wonderfully.

This makes absolutely no sense to me, any ideas?


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PostPosted: Thu May 25, 2017 8:18 am 
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Certified Bonneville Nut
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Joined: Tue May 27, 2008 8:53 am
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Location: Las Cruces, NM
Year and Trim: 1993 Buick Park Avenue
1994 Buick Regal Custom
The polarity was reversed is my only guess. Overvoltage would have at least flashed brightly before it went.

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PostPosted: Thu May 25, 2017 8:56 am 
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Year and Trim: 2004 GXP, 2008 STS, 2008 DTS
Unless there is other logic circuitry involved, or polarity sensitive components such as an electrolytic or tantalum capacitor, reverse polarity should not have caused the LED's to pop. Since these are solid state devices, they will only bias on with current flow in the correct direction. If the LED's were backwards, they simply would not have illuminated because current will not flow backwards through them.

It's too difficult to get anything meaningful from the photo.

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